Final answer:
The perimeter of a Koch snowflake sequence is infinite.
Step-by-step explanation:
The perimeter of a Koch snowflake sequence is actually infinite (option A).
A Koch snowflake is created by repeatedly replacing the middle third of each line segment with an equilateral triangle. This process is continued infinitely. Each iteration adds a certain amount of length to the shape, which means that the perimeter keeps increasing with every iteration. Since the process is repeated infinitely, the perimeter of the Koch snowflake sequence is infinite.