Final answer:
To find the number of grams of NaF formed when 0.500 mole of HF reacts with excess Na₂SiO₃, you can use the balanced chemical equation and the molar mass of NaF.
Step-by-step explanation:
To find the number of grams of NaF formed when 0.500 mole of HF reacts with excess Na₂SiO₃, we need to use the balanced chemical equation and the molar mass of NaF. The balanced equation is 2HF + Na₂SiO₃ → 2NaF + SiO₂ + H₂O.
From the equation, we can see that for every 2 moles of HF, we get 2 moles of NaF. The molar mass of NaF is 41.99 g/mol.
Therefore, for 0.500 mole of HF, we will get 0.500 mole of NaF. To convert moles to grams, we multiply by the molar mass: 0.500 mole x 41.99 g/mol = 20.995 g.