Final answer:
Yes, the function f(x) = 1/x is uniformly continuous on the interval (0,1).
Step-by-step explanation:
Yes, the function f(x) = 1/x is uniformly continuous on the interval (0,1).
A function is uniformly continuous if for any positive real number ε, there exists a positive real number δ such that whenever |x - y| < δ, it implies |f(x) - f(y)| < ε.
In this case, let's choose ε to be a positive real number. We can choose δ to be the minimum of 1/2 and ε/2. Then, whenever |x - y| < δ, we can show that |f(x) - f(y)| < ε.