Question

S the concentration of sodium ions in 0.200 M Na₃PO₄?

A) 0.200 M
B) 0.400 M
C) 0.600 M
D) 0.800 M

Answer 1

The concentration of sodium ions in a 0.200 M solution of Na3PO4 is determined by multiplying the molarity of Na3PO4 by the number of sodium ions it dissociates into, resulting in a concentration of 0.600 M for sodium ions.

Step-by-step explanation:

The question asks for the concentration of sodium ions in a 0.200 M solution of Na3PO4. Sodium phosphate, Na3PO4, dissociates into three sodium ions (Na+) and one phosphate ion (PO43-) in solution. Therefore, for every 1 mole of Na3PO4 dissolved, 3 moles of Na+ ions are produced. To find the concentration of sodium ions, you multiply the concentration of Na3PO4 by 3:

(0.200 M Na3PO4) × 3 = 0.600 M Na+

Thus, the concentration of sodium ions in the solution is 0.600 M, which corresponds to answer choice C).