32.2k views
0 votes
A fair die is rolled 3 times. What is the probability of obtaining no '6's?

A) 125/216
B) 1/216
C) 91/216
D) 125/36

User Dana Gray
by
8.1k points

1 Answer

7 votes

Final answer:

To find the probability of obtaining no '6's when rolling a fair die 3 times, multiply the probability of not rolling a '6' on each individual roll together. The answer is 125/216.

Step-by-step explanation:

To find the probability of obtaining no '6's when rolling a fair die 3 times, we need to calculate the probability of not rolling a '6' on each individual roll and then multiply those probabilities together.


  1. The probability of not rolling a '6' on a single roll is 1 - (1/6) = 5/6.
  2. Since the rolls are independent, we multiply the probabilities together for each roll.
  3. The probability of not rolling a '6' on all 3 rolls is (5/6) * (5/6) * (5/6) = 125/216.

User Mohamd Ali
by
8.8k points