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An RG9 cable with an outer diameter of .24 inches is being installed in a conduit, along with two miniature RGBHV cables with an outer diameter of .474 inches. If the allowed fill?

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Final answer:

The question deals with the resistance and resistivity of different cables and wires, a fundamental Physics concept taught at the High School level. The resistance is calculated with the formula R = ρL/A, considering factors such as material, length, and area.

Step-by-step explanation:

The subject of the question pertains to resistance and resistivity of various types of cables and wires, which is a topic covered in Physics, particularly within the context of Electricity and Magnetism. The question would most likely be encountered at the High School level, with an advanced student potentially encountering this content.

To find the resistance of a cable or wire, one would use the formula R = ρL/A, where ρ is the resistivity of the material, L is the length of the conductor, and A is the cross-sectional area. This formula is derived from Ohm's Law and principles of physical conductivity. In these problems, one would calculate the cross-sectional area using the diameter of the wire, often converting from gauge to standard metric units. Factors like temperature, type of material (such as copper or aluminum), and dimensions of the wire play a crucial role in determining resistance.

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