Question

At equilibrium a 1-L flask contains 0.15mol H₂, 0.25 mol N2, and 0.10mol NH3. Calculate the Keq for 2NH₃ ------> N₂+3H₂

A) 3.2 x 10²
B) 5.6 x 10⁻²
C) 8.4 x 10⁻²
D) 1.2 x 10⁻³

Answer 1

The equilibrium molar concentration of NH3 is 3.2 x 10².

Step-by-step explanation:

To calculate the equilibrium molar concentration of NH3, you can use the equilibrium constant (Keq) expression. The balanced equation for the reaction is 2NH3 ⇌ N2 + 3H2. Keq is equal to the concentration of the products raised to the power of their coefficients divided by the concentration of the reactants raised to the power of their coefficients.

Keq = [N2]^1 * [H2]^3 / [NH3]^2

Plugging in the given concentrations:

Keq = (1.2)^1 * (0.24)^3 / (0.15)^2 = 3.2 x 10²