Question

The reactant side of the complete ionic equation for the reaction between hydrofluoric acid and strontium hydroxide would be..

a. HF(aq) + Sr(OH)2(aq) →
b. 2HF(aq) + Sr2(aq) + 2OH(aq) →
c. HFlag) Sr?"(aq) + OH(aq) → HF(aq) + OH(aq) →
d. H'laq) + Flaq) + Sr2(aq) + OH(aq) →

Answer 1

The reactant side of the complete ionic equation for the reaction between hydrofluoric acid and strontium hydroxide is HF(aq) + Sr(OH)2(aq) → H+(aq) + F-(aq) + Sr2+(aq) + 2OH-(aq).

Step-by-step explanation:

The reactant side of the complete ionic equation for the reaction between hydrofluoric acid and strontium hydroxide would be:

a. HF(aq) + Sr(OH)2(aq) →

To write the complete ionic equation, we need to break up all soluble compounds into their respective ions. Since both hydrofluoric acid and strontium hydroxide are soluble, they will dissociate into their ions:

HF(aq) + Sr(OH)2(aq) → H+(aq) + F-(aq) + Sr2+(aq) + 2OH-(aq)

The complete ionic equation represents the dissociation of all soluble compounds into their ions.