Final answer:
The molecule CHCl₃ has four bonding pairs—one C-H bond and three C-Cl bonds—and zero lone pairs on the central carbon atom. Therefore, the correct answer is option C) 4 bonding pairs, 0 lone pairs.
Step-by-step explanation:
The question is asking to identify the number of bonding pairs and lone pairs in the molecule CHCl₃. Carbon (C) forms four covalent bonds in organic compounds, including CHCl₃. Hence, there are four one with hydrogen (H) and three with chlorine (Cl) atoms, as carbon has four valence electrons and uses one to form a bond with each of the other atoms. Chlorine has seven valence electrons and uses one to form a bond with carbon, leaving six electrons which are organized intoper chlorine atom. However, these lone pairs are on the chlorine atoms and not on the central carbon atom. The central carbon does not have any lone pairs in this molecule. Therefore, CHCl₃ has four bonding pairs and zero lone pairs on the central carbon atom, which corresponds to option C).
The molecule CHCl₃, also known as chloroform, consists of one carbon atom bonded to three chlorine atoms and one hydrogen atom. In chloroform, there are 3 bonding pairs between carbon and the three chlorine atoms. There is 1 lone pair on the carbon atom. The lone pair is not involved in bonding and is not shared with any other atom.