Final answer:
To find the limiting reagent for NaOH + HCl, compare the moles of each reactant and determine which one is completely consumed. In this case, the HCl is the limiting reagent.
Step-by-step explanation:
How to Find the Limiting Reagent for NaOH + HCl
In order to find the limiting reagent for the reaction between NaOH and HCl, you need to compare the amount of each reactant available and determine which one will be completely consumed first. The limiting reagent is the reactant that is completely consumed, while the excess reagent is the one that is left over.
To find the limiting reagent, you can use the stoichiometry of the balanced chemical equation for the reaction. In this case, the balanced equation is:
HCl + NaOH → NaCl + H2O
You can convert the given information into moles and compare the number of moles of each reactant. The reactant with the smaller number of moles is the limiting reagent. In the given example, it is mentioned that 1 mL of 0.10 M NaOH contains 1.0 × 10¯4 mol of NaOH, while the concentration of HCl is 1.8 × 10-5 M. Therefore, the HCl is the limiting reagent, and the NaOH is in excess.