Question

Point A is located at (-2,-4). The midpoint of the line segment AC is point B (6,8). What are the coordinates of point C ?

Answer 1

Point C (14,20) this is the answer

Answer 2

Explanation:

`Midpoint of AC = \left((x_(1)+x_(2))/(2),(y_(1)+y_(2))/(2) \right)\\\\x_(1)=-2 \ and \ y_(1)=-4\\\\\left((-2+x_(2))/(2),(-4+y_(2))/(2) \right) = \left(6 ,8 \right)\\\\\\Compare \ x-coordinates \ and \ y-coordinates\\\\(-2+x_(2))/(2)=6 \ ; (-4+y_(2))/(2)=8`

-2 + x₂ = 6*2 ; -4 + y₂ = 8*2

-2 + x₂ = 12 ; -4 + y₂ = 16

x₂ = 12+2 ; y₂ = 16+4

x₂ = 14 ; y₂ = 20

Point C(14, 20)