Question

A rectangle has a perimeter 112 ft. Its length is 4 feet greater than its width. Find the dimensions of the rectangle.

Answer 1

Explanation:

Petimeter=2L+2w

width=x unknown

length=x+4

P=2L+2W

112= 2(x+4)+2x

112=2x+8+2x

112=4x+8

subtract 8 on both sides

104=4x

divide by 4

x=26

width is 26

length is 30

check 26+36+30+30=112