Question

Using a first-class lever, an effort force (E) of 22 pounds is placed 7.5 feet from the fulcrum (ED) and used to lift a load of 105 pounds (R). What distance from the fulcrum (RD)

was the resistance or load? Use the relationship Effort force multiplied by effort distance is equal to resistance force (load) multiplied by resistance distance. Enter your answer to the
nearest tenth of a foot. Do NOT include units with your answer.
105 lb
Type your answer.
7.5 ft
22 lb
D

Answer 1

7.5 feet since the load was in relationship with the load

Answer 2

To find the resistance distance (RD) from the fulcrum when using a first-class lever, plug the given values into the torque balance equation and solve for RD. In this case, the resistance distance is 1.6 feet.

Step-by-step explanation:

When using a first-class lever, we apply the principle of moments or the balance of torques that states 'Effort force multiplied by effort distance equals resistance force multiplied by resistance distance'. Given an effort force (E) of 22 pounds placed 7.5 feet from the fulcrum (ED) and a load of 105 pounds (R), we can set up the equation:

Effort force (E) × Effort distance (ED) = Resistance force (R) × Resistance distance (RD)

22 lb × 7.5 ft = 105 lb × RD

To find RD, we simply divide:

RD = (22 lb × 7.5 ft) / 105 lb

The units of pounds cancel out, and we calculate:

RD = 165 / 105 = 1.5714 feet

When rounded to the nearest tenth of a foot, the resistance distance (RD) is 1.6 feet.