Answer:
A. 0.0625 moldm¯³
B. 6.125 gdm¯³
Step-by-step explanation:
We'll begin by writing the balanced equation balance equation for the reaction. This is illustrated below:
2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O
From the balanced equation above,
The mole ratio of the acid, H₂SO₄ (nₐ) = 1
The mole ratio of the base, NaOH (n₆) = 2
A. Determination of the concentration of the acid in moldm¯³.
Volume of base, NaOH (V₆) = 20 cm³
Concentration of base, NaOH (C₆) = 0.2 moldm¯³
Volume of acid, H₂SO₄ (Vₐ) = 32 cm³
The mole ratio of the acid, H₂SO₄ (nₐ) = 1
The mole ratio of the base, NaOH (n₆) = 2
Concentration of acid, H₂SO₄ (Cₐ) =?
CₐVₐ / C₆V₆ = nₐ / n₆
Cₐ × 32 / 0.2 × 20 = 1 / 2
Cₐ × 32 / 4 = 1 / 2
Cross multiply
Cₐ × 32 × 2 = 4 × 1
Cₐ × 64 = 4
Divide both side by 64
Cₐ = 4 / 64
Cₐ = 0.0625 moldm¯³
Therefore, concentration of the acid in moldm¯³ is 0.0625 moldm¯³
B. Determination of the concentration of the acid in gdm¯³.
Concentration (moldm¯³) = 0.0625 moldm¯³
Concentration (gdm¯³) =?
Next, we shall determine the molar mass of the acid, H₂SO₄. This can be obtained as follow:
Molar mass of H₂SO₄ = (2×1) + 32 + (4×16)
= 2 + 32 + 98
= 98 g/mol
Finally, we shall determine the concentration of the acid in gdm¯³. This can be obtained as follow:
Concentration (moldm¯³) = 0.0625 moldm¯³
Molar mass of H₂SO₄ = 98 g/mol
Concentration (gdm¯³) =?
Conc. (moldm¯³) = conc. (gdm¯³) / Molar mass
0.0625 = Conc. (gdm¯³) / 98
Cross multiply
Conc. (gdm¯³) = 0.0625 × 98
Conc. (gdm¯³) = 6.125 gdm¯³
Thus, the concentration of the acid in gdm¯³ is 6.125 gdm¯³