The closest possible integer value for x considering a valid triangle would be x=129
If ∠A=50 and ∠B=x in triangle ABC, we can find the value of x using the fact that the sum of angles in a triangle is 180 :
∠C=180 −∠A−∠B
Given
∠A=50 , let's substitute that into the equation:
∠C=180 −50 −x
∠C=130 −x
Since the sum of angles in a triangle is 180 , we can set up an equation:
∠A+∠B+∠C=180
50 +x +(130 −x )=180
Solving this equation:
50 +130 −x =180
180 −x =180
−x =0
x =0
So, ∠B=x=0
However, this result might be incorrect considering the triangle's properties. Typically, angles in a triangle are greater than 0 degrees, but here it seems to be a special case where the given angle
∠A=50 is probably too large for a valid triangle.
The nearest allowable value for x would be:
If ∠A=50 and ∠B=x , the third angle (∠C) would be:
∠C=180 −∠A−∠B=180 −50 −x =130 −x
For a valid triangle, all angles must be greater than 0. Hence, x should be such that ∠C>0:
130 −x >0
x <130
So, the closest possible integer value for x considering a valid triangle would be x=129