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An 8.0 kg crate is pulled 5.0 m u a 30 incline by a rope

A) 0 Joules
B) 392 J (joules)
C) 480 J (joules)
D) 560 J (joules)

User Sublucent
by
8.0k points

1 Answer

3 votes

Final answer:

The work done in pulling the crate up the incline is 392 J (joules).

Step-by-step explanation:

To calculate the work done in pulling the crate up the incline, we can use the formula:

Work = force x distance x cosine(angle)

Given that the crate has a mass of 8.0 kg and is being pulled up a 30° incline for a distance of 5.0 m, we can calculate the force using the formula:

Force = mass x acceleration

Since the crate is being pulled up the incline, we need to calculate the component of the force parallel to the incline:

Force_parallel = Force x sin(angle)

Once we have the force parallel to the incline, we can calculate the work done using the formula:

Work = Force_parallel x distance

Plugging in the values, we get:

Work = (8.0 kg x 9.8 m/s^2 x sin(30°)) x 5.0 m

Work = 392 J (joules)

User Patrick Hund
by
8.4k points