Final answer:
The percent composition of Ba in Ba(NO₃)₂ is 52.57%.
Step-by-step explanation:
The percent composition of Ba in Ba(NO₃)₂ can be calculated by determining the molar mass of Ba(NO₃)₂ and then finding the molar mass of Ba in that compound. Ba(NO₃)₂ has a molar mass of 261.34 g/mol. The molar mass of Ba is 137.33 g/mol. To find the percent composition of Ba, divide the molar mass of Ba by the molar mass of Ba(NO₃)₂ and multiply by 100:
Percent composition of Ba = (molar mass of Ba / molar mass of Ba(NO₃)₂) x 100 = (137.33 g/mol / 261.34 g/mol) x 100 = 52.57%