Answer:
Trial 1 is the largest, trial 3 is the smallest
Step-by-step explanation:
Given:
Trial 1
M₁ = 6·10²² kg
d₁ = 3 500 km = 3.5·10⁶ м
Trial 2
M₂ = 6·10²² kg
d₂ = 7 000 km = 7·10⁶ м
Trial 3
M₃ = 3·10²² kg
d₃ = 7 000 km = 7·10⁶ м
___________
F - ?
Gravitational force:
F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m (N)
F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m (N)
F₃ = G·m·M₃ / d₃² = m·6.67·10⁻¹¹·3·10²² / (7·10⁶)² = 0.04·m (N)
Trial 1 is the largest, trial 3 is the smallest