Answer: -98
Explanation:
Using log knowledge you can simplify this original question to be
![c\sqrt[3]{b^2} \sqrt[3]{c}](https://img.qammunity.org/2024/formulas/mathematics/college/g6578frcaxrzvkhtfhjuk6krkofh7fhx3m.png)
Knowing this is divided by a^8 we can simplify this even further by being
![log(c) + log(\sqrt[3]{b^2}) +log(\sqrt[3]{c})](https://img.qammunity.org/2024/formulas/mathematics/college/8o2eur8krx860jy8q84qy8umlpeq3fcwzp.png)
Finally after rewriting log(a^8) as

We finally are left with the equation
![log(c)+log(\sqrt[3]{b^2} )+log(\sqrt[3]{c} )-8log(a)](https://img.qammunity.org/2024/formulas/mathematics/college/mq9m6iethw480gaj3gvl1s19uxta390bj2.png)
Plugging in the values you provided
This equates to
-9 - 6 - 3 - 80
Which is equal to -98