Question

The sum of three numbers is 61. The second number is 5 times the first, while the third is 2 less than the first. Find the numbers

Answer 1

The first number is 9, the second number is 45, and the third number is 7.

Step-by-step explanation:

Let's assign variables to the three numbers.

Let the first number be x, the second number be 5x, and the third number be x - 2.

We know that the sum of the three numbers is 61,

so we can write the equation: x + 5x + (x - 2) = 61.

Combining like terms, we have: 7x - 2 = 61.

Adding 2 to both sides, we get: 7x = 63.

Dividing both sides by 7, we find that x = 9.

Substituting this value back into the equation, we can find the other two numbers.

Therefore, the three numbers are 9, 45, and 7.