Answer:
See the answer below
Step-by-step explanation:
First, let us assume that the allele for free ear lobes to be represented by A. Thus, the recessive attached earlobe would be a.
The genotype for the heterozygous parents would each be Aa.
Aa x Aa
AA Aa Aa aa (see the attached image for the Punnet's square)
Offspring:
1/4 AA - free ear lobes
1/2 Aa - free ear lobes
1/4 aa - attached ear lobes
Hence
Probability of the child having free ear lobes = 3/4 or 75%
Probability of the child having attached ear lobes = 1/4 or 25%