Final answer:
The maximum gallons per minute (gpm) flow rate of the R-12's defuel pump is approximately 6 gpm.
Step-by-step explanation:
The maximum gallons per minute (gpm) flow rate of the R-12's defuel pump can be calculated using the given information. We know that gasoline contains about 34 MJ per liter. Let's convert the flow rate of 6 gallons per minute to liters per second. One gallon is approximately equal to 3.785 liters. Therefore, the flow rate in liters per minute is 6 x 3.785 = 22.71 L/min. Converting this to liters per second, we divide by 60, giving us 0.3785 L/s. Now, we can calculate the maximum flow rate in gpm.
To convert from liters per second to gallons per minute, we use the conversion factor: 1 gallon is approximately equal to 3.785 liters. Therefore, the maximum flow rate in gpm is approximately 0.3785 L/s x (1 gal/3.785 L) x (60 s/min) = 6 gpm. So, the maximum gpm flow rate of the R-12's defuel pump is 6.