Question

If 0.400 mol of Cl2 reacts with excess SO2, how many moles of ClO2 are formed

Answer 1

When 0.400 mol of Cl2 reacts with excess SO2, 0.400 mol of ClO2 is formed. This is based on the balanced chemical equation
`2Cl_(2) + 2SO_(2)` →
`2Cl_(2) + 2SO_(2)`.

To determine the number of moles of
`2Cl_(2)` formed when 0.400 mol of
`Cl_(2)` reacts with excess
`SO_(2)`:

1. Write the balanced chemical equation for the reaction:

`2Cl_(2) + 2SO_(2)` →
`2Cl_(2) + 2SO_(2)`

2. Determine the stoichiometry of the reaction:

From the balanced equation, it is clear that 2 moles of
`Cl_(2)` react to form 2 moles of
`ClO_(2)`.

3. Use the stoichiometry to calculate the moles of
`ClO_(2)` formed:

Since the stoichiometric ratio between
`Cl_(2)` and
`ClO_(2)` is 1:1, the number of moles of
`ClO_(2)` formed will be the same as the number of moles of
`Cl_(2)` used.

Therefore, when 0.400 mol of
`Cl_(2)` reacts, 0.400 mol of
`ClO_(2)` will be formed.