Final answer:
To calculate the intensity level of a sound that is at 45 decibels, you can use the decibel formula β (dB) = 10 log₁₀ (I/I₀) and solve for 'I'.
After rearranging the formula and solving, the intensity level is found to be 10⁻¹⁷ watts per square meter.
Therefore, the value of the exponent is "-17".
Step-by-step explanation:
The question asks for the intensity level of a sound that registers 45 decibels.
To find the corresponding intensity level in watts per square meter, we use the formula β (dB) = 10 log₁₀ (I/I₀), where 'I' is the sound intensity in watts per square meter and 'I₀' is the reference intensity, which is 10⁻¹² W/m² (the threshold of hearing).
First, we rearrange the formula to solve for 'I':
45 = 10 log₁₀ (I/10⁻¹²)
4.5 = log₁₀ (I/10⁻¹²)
10⁴¹⁵ = I/10⁻¹²
I = 10⁴¹⁵ × 10⁻¹²
I = 10⁻¹⁷ W/m²