Final answer:
The acceleration of the object that was initially at rest and moved 250m in 17s is calculated using the kinematic equation s = ut + ½at^2. With initial velocity u = 0 m/s, we find the acceleration to be approximately 1.73 m/s^2.
Step-by-step explanation:
To calculate the acceleration of an object that was initially at rest, we can use the kinematic equation for uniformly accelerated motion:
s = ut + ½at2
Here, s represents the displacement, u is the initial velocity, a is the acceleration, and t is the time.
Since the object starts at rest, we know u = 0 m/s. We are given that s = 250 m and t = 17 s.
Substituting these values into the equation gives:
250 m = 0 m/s (17 s) + ½a(17 s)2
We can now solve for a:
250 m = ½a(289 s2)
Multiplying both sides by 2:
500 m = a(289 s2)
Dividing both sides by 289 s2 gives:
a = 500 m / 289 s2
a \u2248 1.73 m/s2
The acceleration of the object is therefore approximately 1.73 m/s2.