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If dt has endpoints d(2,2) and t(6,4). what is the equation of the perpendicular bisector of dt

User Xhg
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Final answer:

The equation of the perpendicular bisector of dt is y - 3 = -2(x - 4).

Step-by-step explanation:

To find the equation of the perpendicular bisector of DT, we first need to find the midpoint of the segment DT.

The midpoint is the average of the x-coordinates and the average of the y-coordinates of the endpoints.

In this case, the midpoint is ((2+6)/2, (2+4)/2) = (4, 3).

Next, we need to find the slope of DT.

The slope of a line passing through two points (x1, y1) and (x2, y2) is given by (y2-y1)/(x2-x1).

In this case, the slope of DT is:

(4-2)/(6-2)

= 2/4

= 1/2.

The slope of the perpendicular bisector of DT is the negative reciprocal of the slope of DT.

So, the slope of the perpendicular bisector is -2.

Finally, we can use the point-slope form of a line to find the equation of the perpendicular bisector.

The point-slope form is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Using the midpoint (4, 3) as the point, the equation of the perpendicular bisector is y - 3 = -2(x - 4).

User Elizabethmeyer
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