The given equation represents an ellipse with center (2, 6), semi-major axis of length 2√6, and semi-minor axis of length 26.
The given equation x² + 4y - 4x24y+4=0 can be rearranged to represent an ellipse.
The standard form of the equation for an ellipse is:

where (h, k) is the center of the ellipse, a is the length of the semi-major axis, and b is the length of the semi-minor axis.
To rewrite the given equation in standard form, complete the square for both 2 and y:
x²-4x+4+4y24y+4= 24
(x-2)²+4(y-6) = 24
Now, divide both sides by 24 to get the standard form:

So, the given equation represents an ellipse with center (2, 6), semi-major axis of length 2√6, and semi-minor axis of length 26.
Question
Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse:x^2+4y-4x-24y+4=0