The vertical asymptote of f(x)=log_3 (x) is x=0. At this point, x = 0, y = undefined.
The function f(x)=log_3 (x) has a vertical asymptote where the logarithm is undefined.
In this case, the logarithm function is undefined for x≤0 because you cannot take the logarithm of a non-positive number.
so, for f(x)=log_3 (x), the vertical asymptote is x=0.
As for finding specific x and y values, consider an example. Let's find the value of the function at x=1:
f(1)=log_3 (1)Remember that
log_3 (1) equals 0 because any number raised to the power of 0 equals 1. So, f(1)=0.
For another example, let's find the value of the function at x=9:
f(9)=log_3(9)
log_3 (9) can be rewritten as 2^2 since 3^2=9 Therefore, f(9)=2.