(1) Equations:
and S(100) = 49 =
. (2) Values: a = 105 and
.
Let's use the given data to write two equations and then solve for the constants a and b.
The general form of the model is
, where S(d) is the noise level in decibels at a distance d from the turbine.
1. Equation 1 using the point (0, 105):
When
, so at d = 0, the noise level is a decibels.
Therefore, a = 105.
Equation 1:
![\[S(0) = 105 = ab^0 = a\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/nzbhbpah2hr1n0qxxhac8t4giwlxsk6uu3.png)
2. Equation 2 using the point (100, 49):
When
.
Therefore,

Equation 2:
![\[S(100) = 49 = ab^(100)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/lt0jzsjcna6nkpf6fdtxvaqt46jebjub0w.png)
Now we have a system of two equations:
![\[\begin{align*}1. & \quad a = 105 \\2. & \quad ab^(100) = 49 \\\end{align*}\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/w4i2phut3gie5rclo6sjafr2c4iqa416ry.png)
Let's solve for b using equation 2:
![\[105b^(100) = 49\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/nnji294rhyko8vezlwl9njzsspa0t46s3n.png)
Now, divide both sides by 105:
![\[b^(100) = (49)/(105)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/n0r6kzl3rn463ww7v07cad2o0g8mgcs2de.png)
Take the 100th root of both sides:
![\[b = \left((49)/(105)\right)^{(1)/(100)}\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/puazxxxpmjveo45atujcz0smgn2d8sueqb.png)
Now you can calculate the values for b. Once you have b, you can substitute it back into equation 1 to find the value for a.
Let's finish the calculations:
From the previous steps, we found:
![\[ b = \left((49)/(105)\right)^{(1)/(100)} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kcf7k94fw59a3z85lrakr4ffct6rykr005.png)
Now, let's calculate the value of b:
![\[ b \approx 0.9709 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/wugygdbpdfau6zs9g6chldqmsvc4v3qz7i.png)
Now that we have the value for b, we can substitute it back into Equation 1 to find a:
a = 105
So, the values for the constants are:
![\[ a = 105 \]\[ b \approx 0.9709 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/lx05cw8416kx1zy2xr63otqvgwdut8s6ch.png)
Therefore, the model for the noise level S(d) in decibels at a distance d from the turbine is:
![\[ S(d) = 105 * (0.9709)^d \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/qm5j0sb3i6ms4o98tcnkxjguldyla78cs4.png)
The complete question is:
A wind turbine uses the power of wind to generate electricity. The blades of the turbine make a noise that can be heard at a distance from the turbine. At a distance of d = 0 from the turbine, the noise level is 105 decibels. At a distance of d = 100 meters from the turbine, the noise level is 49 decibels. The house level can be modeled by the function S is given by S(d) = ab^d , where S(d) is the noise level, in decibels, at a distance of d meters from the turbine
(1) Use the given data to write two equations that can be used to find the values for constants a and b in the expression for S(d).
(1) Find the values for a and b