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X y-3z=8 2x-3y z=-6 3x 4y-2z=20

1 Answer

6 votes

The value x=−8.5

y=15.5

z = 1/2 .

Let's solve the system of equations:

x+y−3z=8

2x−3y+z=−6

3x+4y−2z=20

We can solve the system of equations using elimination.

Steps to solve:

1. Eliminate y:

Multiply the top equation by 3 and the bottom equation by 5:

3x+3y−9z=24

10x−15y+5z=−30

Add the top and bottom equations:

13x−12z=−6

Divide both sides by -12:

x+z=1/2

2. Substitute z back into the top equation:

x+y−3(1/2)=8

x+y−3/2=8

x+y=19/2

3. Solve for y:

y=19/2−x

4. Substitute y back into the equation x+z=1/2:

x+(19/2−x)=1/2

2x+19=2

2x=−17

x=−8.5

5. Substitute x back into the equation y=19/2-x:

y=19/2−(−8.5)

y=19/2+8.5

y=15.5

Question

Solve the following system of equations algebraically using linear combinations and substitutions .

x+y−3z=8

2x−3y+z=−6

3x+4y−2z=20

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