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The true power in a 2 amp series RL circuit with a 100 ohm resistor is ?

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Final answer:

The true power in a 2 amp series RL circuit with a 100 ohm resistor is 400 watts.

Step-by-step explanation:

In a 2 amp series RL circuit with a 100 ohm resistor, the true power can be determined using the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.

Substituting the given values, we have P = (2 A)^2 * 100 Ω = 4 A^2 * 100 Ω = 400 W.

Therefore, the true power in the given circuit is 400 watts.

User Matthieu Moy
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