Final answer:
The correct product obtained by the reaction of ethyne with HBr is vinyl bromide, which is represented as HC≣C-Br + H₂.
Step-by-step explanation:
The reaction of an alkyne with HBr (hydrogen bromide) involves the addition of a hydrogen atom and a bromine atom across the triple bond. The correct structure of the product obtained by the complete reaction of ethyne (HC≣CH) with HBr is:
a) HC≣CH + HBr → HC≣C-Br + H₂
This indicates that hydrogen adds to one carbon atom and bromine adds to the other carbon atom of the alkyne, resulting in a vinyl bromide. None of the other options correctly represent the addition of HBr to an alkyne.