Question

Which of the following iterative methods is equivalent to this recursive method?

A) n⋅foo(n−1)
B) n+foo(n−1)
C) foo(n−1)−n
D) foo(n−1)+n

Answer 1

Without the recursive method explicitly defined, it's not possible to decide which iterative method is equivalent. Assuming typical patterns, if the recursive method is factorial-like, then option A is equivalent iteratively, and if it's an arithmetic series, then option B is equivalent.

Step-by-step explanation:

The recursive method mentioned is not clearly stated, so I'm assuming that the desired goal is to determine which of the iterative methods would produce the same sequence or result as a given recursive one. To represent a recursive method equivalently in an iterative form, we need to know the base case and the way the function foo changes with each recursion.

If the recursive function is defined as foo(n) = n · foo(n-1), with a base case, such as foo(1) = 1, this would produce a sequence equivalent to factorial, where each term is the product of all integers from 1 to n. If the recursive function is foo(n) = n + foo(n-1), with some base case, it would create an arithmetic series.

Without a specific definition, it's impossible to provide an exact equivalent, but in general, the equivalent iterative methods for these recursive methods would involve loops and might look something like this:

for(int i = 1; i <= n; i++) {
result *= i; // For option A
}
for(int i = 1; i <= n; i++) {
result += i; // For option B
}