Question

Heat is lost to the styrofoam calorimeter. Assuming a 6.22°C temperature change for the reaction of HCl with NaOH, calculate the:

a) Enthalpy change of the reaction
b) Heat absorbed by the reactants
c) Heat lost to the surroundings
d) Specific heat of the reaction

Answer 1

To calculate the enthalpy change of the reaction, use the equation q = mcΔT. The heat absorbed by the reactants is equal to the enthalpy change. You can find the specific heat of the reaction by rearranging the equation q = mcΔT.

Step-by-step explanation:

The enthalpy change of the reaction can be calculated using the equation q = mcΔT, where q is the heat absorbed or released, m is the mass of the solution, c is the specific heat of the solution, and ΔT is the temperature change. In this case, the temperature change is 6.22°C.

To calculate the enthalpy change, we need to know the mass of the solution. Since the density of the solution is given as 1.00 g/mL and the total volume of the solution is 200.0 mL, the mass of the solution is 200.0 g.

Using the equation q = mcΔT, we can calculate the heat absorbed by the reactants, which is equal to the enthalpy change of the reaction.

The specific heat of the reaction can be calculated by rearranging the equation q = mcΔT to solve for c. Since we know the heat absorbed, the mass of the solution, and the temperature change, we can substitute these values into the equation to find the specific heat of the reaction.