Final answer:
When (E)-3-heptene is treated with HCl, an addition of HCl across the double bond occurs, resulting in the formation of a monosubstituted alkyl halide.
Step-by-step explanation:
When (E)-3-heptene is dissolved in ether and treated with HCl, the reaction that occurs is addition of HCl across the double bond. HCl adds to the alkene, with the H atom attaching to one carbon and the Cl atom attaching to the other carbon involved in the double bond. This is a typical example of an electrophilic addition reaction, where the pi bond electrons in the alkene act as a nucleophile and attack the H+ ion of the HCl, leading to the formation of a carbocation intermediate that subsequently reacts with the Cl- ion. This results in the formation of a monosubstituted alkyl halide.
The correct answer to what describes the product(s) of the reaction is therefore a) Addition of HCl across the double bond.