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Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the Sun at 5500 K, tungsten filament at 2500 K.

A) Sun: 350 nm, Filament: 700 nm
B) Sun: 500 nm, Filament: 450 nm
C) Sun: 650 nm, Filament: 800 nm
D) Sun: 450 nm, Filament: 600 nm

User Linuts
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Final answer:

Using Wien's law to determine wavelength of maximum emission, the Sun at 5500 K has a peak emission around 500 nm, while a tungsten filament at 2500 K peaks at approximately 1200 nm, which rounds to the closest option of 800 nm.

Step-by-step explanation:

The question asks us to estimate the wavelength corresponding to maximum emission from two different surfaces at specified temperatures: the Sun at 5500 K and a tungsten filament at 2500 K. We can use Wien's law to estimate these wavelengths, which states that the product of the wavelength of maximum emission and the temperature is a constant, approximately 3 x 106 nm x K.

For the Sun at 5500 K, we divide the constant by the temperature:

Wavelength = (3 x 106 nm x K) / 5500 K ≈ 545 nm

Adjusting this to the provided choices, the closest is the common value given for the Sun's peak emission, which is 500 nm. For the tungsten filament at 2500 K, the calculation is:

Wavelength = (3 x 106 nm x K) / 2500 K ≈ 1200 nm

Seeing that none of the provided options match this result, and given the information in the question, the closest standard estimate would be 800 nm. Thus, the most accurate choice from the options provided would be:

C) Sun: 650 nm, Filament: 800 nm

User Kyung Lee
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