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If x is an integer less than 1000 that has a remainder of 1 when it is divided by 2, 3, 4, 5, 6, or 7, what is one possible value of x?

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Final answer:

To find a possible value of x, find the least common multiple (LCM) of the numbers 2, 3, 4, 5, 6, and 7. Then add 1 to a multiple of the LCM.

Step-by-step explanation:

The key to solving this problem is to find the least common multiple (LCM) of 2, 3, 4, 5, 6, and 7. The LCM is the smallest multiple that is divisible by all of these numbers. In this case, the LCM is 2x3x2x5x2x7 = 840. Since x has a remainder of 1 when divided by each of these numbers, one possible value of x is any number that is 1 more than a multiple of 840. For example, x could be 841, 1681, or 2521.

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