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Find two numbers A and B whose sum A+B is -3 and whose differenceA-B is 5.

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Final answer:

To find two numbers A and B whose sum is -3 and whose difference is 5, we can use a system of equations.

By solving this system, we find that the two numbers are A = 1 and B = -4.

Step-by-step explanation:

Let's assign A and B as the unknown numbers.

The sum A+B = -3, so we have the equation A + B = -3.

The difference A-B = 5, so we have the equation A - B = 5.

To solve this system of equations, we can use the method of substitution or elimination.

Let's use the method of substitution.

From the equation A + B = -3, we can isolate A by subtracting B from both sides: A = -3 - B.

Substitute this value of A into the second equation A - B = 5:

(-3 - B) - B = 5

-3 - 2B = 5

-2B = 5 + 3

-2B = 8

B = 8/-2

B = -4

Substitute the value of B back into the first equation to find A:

A + -4 = -3

A = -3 + 4

A = 1

Therefore, the two numbers A and B that satisfy the given conditions are A = 1 and B = -4.

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