Question

Find two numbers n and m for which -0.5m + 2n = 12 and 3n+3m = 33.

Answer 1

To find two numbers n and m that satisfy the system of equations -0.5m + 2n = 12 and 3n+3m = 33, use the elimination method to get n = 15.33 and m = -4.33.

Step-by-step explanation:

Let's use the elimination method.

First, make the coefficients of m or n the same in both equations.

Multiply the first equation by 3 to get:

• -1.5m + 6n = 36

Now we can add this to the second equation to eliminate m:

• 3n + 3m = 33
• -(1.5m - 6n = 36)

This yields:

4.5n = 69

Divide by 4.5 to get:

n = 15.33

Now plug the value of n into the second equation to find m:

3(15.33) + 3m = 33

3m = 33 - 3(15.33)

3m = 33 - 46

m = -13/3

The two numbers n and m that satisfy the given system of equations are n = 15.33 and m = -4.33.