Question

An industrial garbage container has a lid weighing 60 N that is uniformly distributed over the 50 cm width of the lid. The support is perpendicular to the lid at the instant shown.

a) What is the force exerted by the lid on the support?

b) What is the torque exerted by the lid on the support?

c) What is the net force acting on the lid?

d) What is the net torque acting on the lid?

Answer 1

The force exerted on the support by the lid is 60 N. The torque depends on the distance to the pivot point which is not provided in the question. If the lid is in equilibrium, both the net force and net torque on the lid are zero.

Step-by-step explanation:

This question pertains to the concepts of net force, torque, and equilibrium in Physics. Specifically, the question involves a situation where a lid of an industrial garbage container exerts a force on the support, which may also involve calculating the torque if the distance from the pivot point to where the force is applied is known.

Answer Details:

1. The force exerted by the lid on the support will be equivalent to the weight of the lid, which is given as 60 N.
2. The torque exerted by the lid on the support depends on the distance from the pivot point to the point where the force is applied; the torque is calculated by the formula τ = Fd, where F is the force and d is the perpendicular distance from the pivot point to the force's line of action.
3. The net force acting on the lid is zero if it is in equilibrium.
4. The net torque acting on the lid is also zero if it is stationary and in rotational equilibrium.