Question

The 500-kg elevator starts from rest and travels upward with a constant acceleration. Determine the power output of the motor M when neglecting the mass of the pulleys and cable.

A) P=1/2mv²
B) P=F⋅v
C) P=F⋅d
D) P=F⋅a

Answer 1

The correct formula to use for calculating the power output of an elevator's motor when accelerating upwards is P = F·v (Option B), as power is the product of force and velocity.

Step-by-step explanation:

The student's question pertains to power output of an elevator's motor when it is accelerating upwards. To determine the power output when the elevator starts from rest and travels upward with a constant acceleration, the correct formula to use is P = F·v (Option B). Power is the rate at which work is performed or energy is transferred, and in the context of an elevator moving with a constant acceleration, it is the product of the force applied by the motor (F) and the velocity of the elevator (v). As the elevator starts from rest, its initial velocity is zero, but as it accelerates, both F and v will have non-zero values, and the motor has to do work against gravity and any present frictional forces.