Final answer:
Electrons from FADH₂ enter the ETC at Complex II, missing the Complex I, which results in a lower ATP yield compared to NADH, which transfers electrons starting from Complex I through to Complex IV.
Step-by-step explanation:
The difference in how FADH₂ and NADH electrons are processed through the electron transport chain (ETC) is a consequence of their respective points of entry. Electrons delivered by NADH enter through Complex I, subsequently being transferred through Complex III and Complex IV, whereas FADH₂ electrons enter the ETC at Complex II, skipping Complex I and then moving to Complexes III and IV.
Complex II directly accepts electrons from the oxidation of FADH₂, using the enzyme succinate dehydrogenase from the citric acid cycle. This process does not involve Complex I and as a result, electrons from FADH₂ do not contribute to the proton gradient establishment at that stage. Hence, the energy released by FADH₂ through the ETC is less compared to NADH, resulting in the production of fewer ATP molecules.
To summarize, the entry of FADH₂ at Complex II means it bypasses the proton pump of Complex I, which directly affects its lower ATP yield in comparison to NADH.