Question

A bird (A) is flying with a velocity of 22 ft per second and an angle of 6 degrees above the horizontal. Find the vertical and horizontal components of the velocity:

(a) Vertical: 22 ft/s, Horizontal: 0 ft/s
(b) Vertical: 0 ft/s, Horizontal: 22 ft/s
(c) Vertical: 22 sin(6°) ft/s, Horizontal: 22 cos(6°) ft/s
(d) Vertical: 22 cos(6°) ft/s, Horizontal: 22 sin(6°) ft/s
(e) Vertical: 22 tan(6°) ft/s, Horizontal: 22 ft/s
(f) Vertical: 22 ft/s, Horizontal: 22 tan(6°) ft/s

Answer 1

The vertical and horizontal components of the velocity of bird (A) flying at 22 ft/s and an angle of 6 degrees above the horizontal are 22 sin(6°) ft/s and 22 cos(6°) ft/s, respectively.

Step-by-step explanation:

The question is asking to find the vertical and horizontal components of the velocity of a bird flying at a certain speed and angle. To calculate the components of the velocity of bird (A), which is flying with a velocity of 22 ft per second at an angle of 6 degrees above the horizontal, we use trigonometric functions. The correct components of the velocity are given by:

• Vertical component: 22 sin(6°) ft/s
• Horizontal component: 22 cos(6°) ft/s

The vertical component of the velocity is found by multiplying the velocity by the sine of the angle, and the horizontal component is found by multiplying the velocity by the cosine of the angle. The correct answer is:

(c) Vertical: 22 sin(6°) ft/s, Horizontal: 22 cos(6°) ft/s