Final answer:
To find the number of ways the math books and English books can be arranged, treat them as single entities and calculate the number of permutations of these two groups.
Step-by-step explanation:
To calculate the number of ways the math books and English books can be arranged, we need to treat the six math books and three English books as single entities. This means that we have a total of 2 groups: one group consisting of the math books, and another group consisting of the English books.
Now, we need to find the number of ways we can arrange these 2 groups. The math books can be arranged in 6! (6 factorial) ways, and the English books can be arranged in 3! (3 factorial) ways. Therefore, the total number of ways to arrange the books is 6! * 3! = 720 * 6 = 4,320.
So, the correct answer is A) 720.