Final answer:
The first equation -2(3x - 1) = -6x - 1, has no solutions.
The second equation 2(3x – 1) = 6x – 2, has infinitely many solutions.
The third equation 2(3x – 1) = –6x – 2, has one solution.
Step-by-step explanation:
1) For the equation -2(3x - 1) = -6x - 1, we can start by simplifying both sides of the equation: -6x + 2 = -6x - 1.
Next, we can add 6x to both sides to eliminate the variable: 2 = -1.
Since this leads to a contradiction, there are no solutions for this equation.
2) For the equation 2(3x - 1) = 6x - 2, we can start by simplifying both sides of the equation: 6x - 2 = 6x - 2.
Next, we can subtract 6x from both sides to eliminate the variable: -2 = -2.
Since this equation is true for all values of x, there are infinitely many solutions.
3) For the equation 2(3x - 1) = -6x - 2, we can start by simplifying both sides of the equation: 6x - 2 = -6x - 2.
Next, we can add 6x to both sides to eliminate the variable: 12x - 2 = -2.
Then, we can add 2 to both sides: 12x = 0.
Finally, we can divide both sides by 12 to solve for x: x = 0.
Hence, there is one solution for this equation.