Question

If a 2 kg ball is moving at 6 m/s to the right and then hits a wall and bounces back at - 4 m/s (left), what is the change in momentum (in kg*m/s)?

Answer 1

Step-by-step explanation:

Givens

delta mv = ?

m = 2 kg

vi = 6 m/s right is positive

vf = - 4 m/s left

Formula

delta mv = m (vf - vi)

Solution

delta mv = 2 * (-4 - 6)

delta mv = 2 * - 10

delta mv = - 20 kg m/s