46,757 views
29 votes
29 votes
if his arms are capable of exerting a force of 14001400 n on the rope, what is the maximum speed he can tolerate at the lowest point of his swing?

User LucaM
by
2.4k points

1 Answer

12 votes
12 votes

Given Data

Mass of tarzan: m=80kg

Length of vine:L=4.8m

Maximum force exerted by tarzan on the vine: F=1400N

The expression of the net force along the direction of vein is

F-mg-mv²/L=0

mv²/L=F-mg

v²=L(F-mg)/m

v=√L(F-mg)/m

Substitute the given values in the above expression.

v=√4.8 kg (1400N-80kg×9.8m/80kg

v≈6.08m/s

Thus, the maximum tolerable speed at the lowest point is 6.08m/s

What is centrifugal acceleration?

Where RV is the vertical curve's radius in meters and v is the speed in meters per second, we can calculate the centrifugal acceleration.

I understand that the question you are looking for

If his arms are capable of exerting a force of 1400Non the rope, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 80 kg and the vine is 4.8m long.

To know more about centrifugal acceleration visit

User Smellerbee
by
2.8k points