Question

Consider the following code segment.

String str = "AP-CSA";
for (int i = 0; i < (); i++)
{
if (str.substring(i, i + 1).equals("A"))
{
System (i + " ");
}
}
What is printed as a result of executing the code segment?
A 0
B 5
C 0 5
D 0 6
E 1 6

Answer 1

The provided Java code prints the indices of the character 'A' found in the string "AP-CSA". After correcting the for loop to run over the length of the string, the output would be '0 5 ', representing the positions of 'A' in the string. The correct option is C 0 5

Step-by-step explanation:

The student is asking about the output of a Java program code segment. In this code, a string variable str is initialized with "AP-CSA". A for loop iterates over the characters of the string, and an if statement checks if the current character is 'A'. If it's an 'A', it prints the index of that character followed by a space.

There is a missing part within the for loop brackets, which should be str.length() to get the proper length of the string for the loop condition. Considering the original code would have this corrected, the sequence that would be printed when the code segment is executed is '0 5 ', because the character 'A' appears at index 0 and index 5 in the given string "AP-CSA".

The code segment provided loops through each character of the string str and prints the position of the character if it is equal to 'A'.

The loop starts at i = 0 and continues as long as i is less than the length of the string str.

Since the string is 'AP-CSA', the loop will find two occurrences of 'A' at positions 0 and 5. Therefore, the code will print '0 5' as the result.

The correct option is C 0 5