Question

An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

Answer 1

- 42

Step-by-step explanation:

m = 6kg

vi = 17 m/s

vf = 10 m/s

delta mv = ?

Formula

delta mv = m*(vf) - m(vi)

delta mv = 6(10 - 17)

delta mv = 6(-7)

delta mv = - 42 kg m/s