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Start with finding the rate of 2S₂O²-


and use stoichiometry and the balanced chemical equation to extrapolate...

Options:

OPTION 1: Product formation
OPTION 2: Reactant consumption
OPTION 3: Catalyst activity
OPTION 4: Equilibrium concentration

1 Answer

4 votes

Final answer:

The equilibrium constant (Ke) for the reaction 2SO₂(g) + O₂(g) → 2SO₃(g) with given concentrations is 3.43 M⁻¹. The reaction quotient (Q) has a similar expression to Ke, using initial concentrations. Reaction rate expressions are written based on the stoichiometry of the reacting species.

Step-by-step explanation:

To calculate the equilibrium constant (Ke) for the reaction 2SO₂(g) + O₂(g) → 2SO₃(g), we use the concentrations of reactants and products at equilibrium. The equilibrium constant expression is Ke = [SO₃]² / ([SO₂]² × [O₂]), where the concentrations are raised to the power of their stoichiometric coefficients in the balanced equation. Plugging in the given concentrations, we obtain Ke = (1.1 M)² / ((0.90 M)² × (0.35 M)) = 3.43 M⁻¹.

The reaction quotient expression (Q) for a general reaction aA + bB → cC + dD is Q = [C]¹¹ / ([A]¹ × [B]²), which parallels the form of the equilibrium constant expression, but uses initial, non-equilibrium concentrations.

For reaction (a) 2SO₂(g) + O₂(g) = 2SO₃(g), the reaction rate expressions can be written as rate = -d[SO₂]/dt = -1/2 × d[O₂]/dt = d[SO₃]/dt, with each term representing the rate of change of concentration of SO₂, O₂, and SO₃, respectively.

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